Quadratic modular equation solver
This Web application can solve equations of the form ax² + bx + c ≡ 0 (mod n) where the integer unknown x is in the range 0 ≤ x < n. In particular, it can find modular square roots by setting a = -1, b = 0, c = number whose root we want to find and n = modulus.
You can type numbers or numerical expressions on the input boxes at the left.
The calculator accepts numbers of up to 1000 digits, but notice that the modulus n should be factored (some large numbers cannot be factored in a reasonable amount of time). The factorization engine is the one used in the Elliptic Curve Method factorization applet, that uses the methods ECM and SIQS.
When a is not zero, the number of solutions depends on the number of distinct prime factor of the modulus, so if the modulus has many small prime factors (say more than 14), the program could run out of memory and it will not show any solution.
You can also enter expressions that use the following operators and parentheses:
- + for addition
- - for subtraction
- * for multiplication
- / for integer division
- % for modulus (remainder of the integer division)
- ^ or ** for exponentiation (the exponent must be greater than or equal to zero).
- <, ==, >; <=, >=, != for comparisons. The operators return zero for false and -1 for true.
- AND, OR, XOR, NOT for binary logic. The operations are done in binary (base 2). Positive (negative) numbers are prepended with an infinite number of bits set to zero (one).
- SHL or <<: When b ≥ 0, a SHL b shifts a left the number of bits specified by b. This is equivalent to a × 2b. Otherwise, a SHL b shifts a right the number of bits specified by −b. This is equivalent to floor(a / 2−b). Example: 5 SHL 3 = 40.
- SHR or >>: When b ≥ 0, a SHR b shifts a right the number of bits specified by b. This is equivalent to floor(a / 2b). Otherwise, a SHR b shifts a left the number of bits specified by −b. This is equivalent to a × 2−b. Example: -19 SHR 2 = -5.
- n!: factorial (n must be greater than or equal to zero). Example: 6! = 6 × 5 × 4 × 3 × 2 = 720.
- n!! ... !: multiple factorial (n must be greater than or equal to zero). It is the product of n times n − k times n − 2k ... (all numbers greater than zero) where k is the number of exclamation marks. Example: 7!! = 7 × 5 × 3 × 1 = 105.
- p#: primorial (product of all primes less or equal than p). Example: 12# = 11 × 7 × 5 × 3 × 2 = 2310.
- B(n): Previous probable prime before n. Example: B(24) = 23.
- F(n): Fibonacci number Fn from the sequence 0, 1, 1, 2, 3, 5, 8, 13, 21, etc. where each element equals the sum of the previous two members of the sequence. Example: F(7) = 13.
- L(n): Lucas number Ln = Fn-1 + Fn+1
- N(n): Next probable prime after n. Example: N(24) = 29.
- P(n): Unrestricted Partition Number (number of decompositions of n into sums of integers without regard to order). Example: P(4) = 5 because the number 4 can be partitioned in 5 different ways: 4 = 3+1 = 2+2 = 2+1+1 = 1+1+1+1.
- Gcd(m,n, ...): Greatest common divisor of these integers. Example: GCD(12, 16) = 4.
- Lcm(m,n, ...): Least common multiple of these integers. Example: LCM(12, 16, 24) = 48.
- Modinv(m,n): inverse of m modulo n, only valid when m and n are coprime, meaning that they do not have common factors. Example: Modinv(3,7) = 5 because 3 × 5 ≡ 1 (mod 7)
- Modpow(m,n,r): finds mn modulo r. Example: Modpow(3, 4, 7) = 4, because 34 ≡ 4 (mod 7).
- Jacobi(m,n): obtains the Jacobi symbol of m and n. When the second argument is prime, the result is zero when m is multiple of n, it is one if there is a solution of x² ≡ m (mod n) and it is equal to −1 when the mentioned congruence has no solution.
- IsPrime(n): returns zero if n is not probable prime, -1 if it is. Example: IsPrime(5) = -1.
- Sqrt(n): Integer part of the square root of the argument.
- NumDigits(n,r): Number of digits of n in base r. Example: NumDigits(13, 2) = 4 because 13 in binary (base 2) is expressed as 1101.
- SumDigits(n,r): Sum of digits of n in base r. Example: SumDigits(213, 10) = 6 because the sum of the digits expressed in decimal is 2+1+3 = 6.
- RevDigits(n,r): finds the value obtained by writing backwards the digits of n in base r. Example: RevDigits(213, 10) = 312.
You can use the prefix 0x for hexadecimal numbers, for example 0x38 is equal to 56.
The exponentiation symbol is not present in some mobile devices, so two asterisks ** can by typed as the exponentiation operator.
Written by Dario Alpern. Last updated 11 September 2021.